What is the monotone f(x)=1+sqrt(3x-6) ?

The monotone f(x)=1+sqrt(3x-6) is Increasing:2<x<infinity

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monotone f(x)=1+sqrt(3x-6)

monotone intervals

f (x) = 1 + 3 x - 6

Increasing : 2 < x < \infty

Solution steps

f^{'} (x) = \frac{3}{2 3 x - 6}

Find intervals:

Increasing

: 2 < x < \infty

Increasing : 2 < x < \infty

lo g_{2} (x) + 8

h (x) = \frac{1}{x}

6 x - 36

f (x) = 2 t - 9 t^{2}

f (x) = 5 - 15 x

What is the monotone f(x)=1+sqrt(3x-6) ?
The monotone f(x)=1+sqrt(3x-6) is Increasing:2<x<infinity