What is the inverse of f(x)= 5/9 (x-32),x>=-459.6 ?

The inverse of f(x)= 5/9 (x-32),x>=-459.6 is (9x)/5+32

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inverse of f(x)= 5/9 (x-32),x>=-459.6

inverse

f (x) = \frac{5}{9} (x - 32), x \geq - 459.6

\frac{9 x}{5} + 32

Solution steps

y = \frac{5}{9} (x - 32)

Replace

x

with

y

x = \frac{5}{9} (y - 32)

Solve for

y, x = \frac{5}{9} (y - 32)

\frac{9 x}{5} + 32

\frac{sin ( 3 x )}{x - sin ( 2 x )}

f (x) = x^{3} - 3 x + 5

y = 3 (x - 2) (x - 4)

sin (x - \frac{π}{4})

f (x) = 2 x + 6 + 2

What is the inverse of f(x)= 5/9 (x-32),x>=-459.6 ?
The inverse of f(x)= 5/9 (x-32),x>=-459.6 is (9x)/5+32