What is the domain of f(x)=sqrt(-8x+9) ?

The domain of f(x)=sqrt(-8x+9) is x<= 9/8

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domain of f(x)=sqrt(-8x+9)

domain

f (x) = - 8 x + 9

x \leq \frac{9}{8}

Interval Notation

(- \infty, \frac{9}{8}]

Solution steps

Find non-negative values for radicals:

x \leq \frac{9}{8}

The function domain

x \leq \frac{9}{8}

\frac{2 x ^{2} + 3}{x ^{2} + 1}

y = - 2

f (x) = 3 x^{2} - 12 x + 4

X^{3}

f (x) = \frac{( 6 - 7 x )}{( 8 - 5 x )}

What is the domain of f(x)=sqrt(-8x+9) ?
The domain of f(x)=sqrt(-8x+9) is x<= 9/8