What is the range of f(x)=(x+5)/(x+2) ?

The range of f(x)=(x+5)/(x+2) is f(x) 1

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range of f(x)=(x+5)/(x+2)

range

f (x) = \frac{x + 5}{x + 2}

f (x) < 1 or f (x) > 1

Interval Notation

(- \infty, 1) \cup (1, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

\frac{x + 5}{x + 2}

Inverse of

\frac{x + 5}{x + 2} : \frac{5 - 2 x}{x - 1}

\frac{5 - 2 x}{x - 1}

Find the domain of each inverse function

Domain of

\frac{5 - 2 x}{x - 1} : x < 1 or x > 1

Combine the intervals

f (x) < 1 or f (x) > 1

f (x) = \frac{12 x ^{2}}{x ^{4} + 36}

f (x) = (x - 4)

x - 6

f (x) = \frac{2}{3 ( x + 3 )}

What is the range of f(x)=(x+5)/(x+2) ?
The range of f(x)=(x+5)/(x+2) is f(x)<1\lor f(x)>1