What is the perpendicular 2x+7y=1,(1,7) ?

The perpendicular 2x+7y=1,(1,7) is y= 7/2 x+7/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

perpendicular 2x+7y=1,(1,7)

perpendicular

2 x + 7 y = 1, (1, 7)

y = \frac{7}{2} x + \frac{7}{2}

Solution steps

Find the line

y = mx + b

perpendicular to

2 x + 7 y = 1

that passes through

(1, 7)

Find the slope of

2 x + 7 y = 1 : m = - \frac{2}{7}

Compute the slope of the perpendicular line:

m_{p} = \frac{7}{2}

Find the line with slope m=

\frac{7}{2}

and passing through

(1, 7) : y = \frac{7}{2} x + \frac{7}{2}

y = \frac{7}{2} x + \frac{7}{2}

f (x) = (x + 1)^{2}

0.5 (x + 4)^{3}

5 x + 1

(4, 4), (9, 5)

f (x) = \frac{x}{3} - \frac{4}{3}

What is the perpendicular 2x+7y=1,(1,7) ?
The perpendicular 2x+7y=1,(1,7) is y= 7/2 x+7/2