What is the inverse of f(x)=((x-6)^{1/2})/7 ?

The inverse of f(x)=((x-6)^{1/2})/7 is 49x^2+6

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inverse of f(x)=((x-6)^{1/2})/7

inverse

f (x) = \frac{( x - 6 ) ^{\frac{1}{2}}}{7}

49 x^{2} + 6

Solution steps

y = \frac{( x - 6 ) ^{\frac{1}{2}}}{7}

Replace

x

with

y

x = \frac{( y - 6 ) ^{\frac{1}{2}}}{7}

Solve for

y, x = \frac{( y - 6 ) ^{\frac{1}{2}}}{7}

49 x^{2} + 6

f (x) = 2 (x + 3)^{2} - 1

f (x) = 9 x^{2}, x \geq 0

f (x) = x^{7} + 3

f (x) = \frac{x ^{2} - 3}{x - 2}

f (x) = - 4 (x - 2)^{2} - 3

What is the inverse of f(x)=((x-6)^{1/2})/7 ?
The inverse of f(x)=((x-6)^{1/2})/7 is 49x^2+6