What is the perpendicular y=-17x+8,(6,-7) ?

The perpendicular y=-17x+8,(6,-7) is y= 1/17 x-125/17

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perpendicular y=-17x+8,(6,-7)

perpendicular

y = - 17 x + 8, (6, - 7)

y = \frac{1}{17} x - \frac{125}{17}

Solution steps

Find the line

y = mx + b

perpendicular to

y = - 17 x + 8

that passes through

(6, - 7)

Find the slope of

y = - 17 x + 8 : m = - 17

Compute the slope of the perpendicular line:

m_{p} = \frac{1}{17}

Find the line with slope m=

\frac{1}{17}

and passing through

(6, - 7) : y = \frac{1}{17} x - \frac{125}{17}

y = \frac{1}{17} x - \frac{125}{17}

y = - 4

f (x) = 3 x - 36 x^{\frac{1}{3}}

f (x) = \frac{5 ( x + 7 )}{7 x}

f (x) = \frac{3}{t}

f (x) = 10 - 5 x

What is the perpendicular y=-17x+8,(6,-7) ?
The perpendicular y=-17x+8,(6,-7) is y= 1/17 x-125/17