What is the domain of f(x)=sqrt(x^2+2x-8) ?

The domain of f(x)=sqrt(x^2+2x-8) is x = 2

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domain of f(x)=sqrt(x^2+2x-8)

domain

f (x) = x^{2} + 2 x - 8

x \leq - 4 or x \geq 2

Interval Notation

(- \infty, - 4] \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 4 or x \geq 2

The function domain

x \leq - 4 or x \geq 2

f (x) = \frac{3}{1 - 3 x}

f (x) = - 3 + 2 lo g_{2} (5 - x)

(4, 1), (9, 1)

y = 2 x + 14

What is the domain of f(x)=sqrt(x^2+2x-8) ?
The domain of f(x)=sqrt(x^2+2x-8) is x<=-4\lor x>= 2