What is the critical f(x)=(x-4)/(x^2+20) ?

The critical f(x)=(x-4)/(x^2+20) is x=-2,x=10

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critical f(x)=(x-4)/(x^2+20)

critical points

f (x) = \frac{x - 4}{x ^{2} + 20}

x = - 2, x = 10

Solution steps

\frac{x - 4}{x ^{2} + 20}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 2, x = 10

Identify critical points not in

f (x)

domain

Domain of

\frac{x - 4}{x ^{2} + 20} : - \infty < x < \infty

All critical points are in domain

x = - 2, x = 10

f (x) = \frac{2 x ^{2} - 20 x}{3 x - 30}

m = - \frac{1}{7}, (7, - 3)

f (x) = \frac{3}{5} x + 3

14

What is the critical f(x)=(x-4)/(x^2+20) ?
The critical f(x)=(x-4)/(x^2+20) is x=-2,x=10