What is the inverse of f(x)=((x+19))/((x-18)) ?

The inverse of f(x)=((x+19))/((x-18)) is (19+18x)/(x-1)

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inverse of f(x)=((x+19))/((x-18))

inverse

f (x) = \frac{( x + 19 )}{( x - 18 )}

\frac{19 + 18 x}{x - 1}

Solution steps

y = \frac{x + 19}{x - 18}

Replace

x

with

y

x = \frac{y + 19}{y - 18}

Solve for

y, x = \frac{y + 19}{y - 18}

\frac{19 + 18 x}{x - 1}

\frac{2}{x + 1} + \frac{x}{x + 1}

x^{3} - 3 x^{2} + 2 x + 1

\frac{1}{3} lo g_{10} (3 x)

(- 7, 5), (7, 3)

ln (x)

What is the inverse of f(x)=((x+19))/((x-18)) ?
The inverse of f(x)=((x+19))/((x-18)) is (19+18x)/(x-1)