What is the domain of f(x)= 1/(x^2-6x-7) ?

The domain of f(x)= 1/(x^2-6x-7) is x 7

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domain of f(x)= 1/(x^2-6x-7)

domain

f (x) = \frac{1}{x ^{2} - 6 x - 7}

x < - 1 or - 1 < x < 7 or x > 7

Interval Notation

(- \infty, - 1) \cup (- 1, 7) \cup (7, \infty)

Solution steps

Find undefined (singularity) points:

x = 7, x = - 1

The function domain

x < - 1 or - 1 < x < 7 or x > 7

f (x) = x^{2} - 2

\frac{9 x}{x ^{2} + x - 2}

y = - x^{2} + 4

f (x) = \frac{1}{x + 1}

f (x) = \frac{4}{x + 1} + 1

What is the domain of f(x)= 1/(x^2-6x-7) ?
The domain of f(x)= 1/(x^2-6x-7) is x<-1\lor-1<x<7\lor x>7