What is the inverse of f(x)=((x-1))/((x+1)) ?

The inverse of f(x)=((x-1))/((x+1)) is (-1-x)/(x-1)

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inverse of f(x)=((x-1))/((x+1))

inverse

f (x) = \frac{( x - 1 )}{( x + 1 )}

\frac{- 1 - x}{x - 1}

Solution steps

y = \frac{x - 1}{x + 1}

Replace

x

with

y

x = \frac{y - 1}{y + 1}

Solve for

y, x = \frac{y - 1}{y + 1}

\frac{- 1 - x}{x - 1}

\frac{8 x}{8 + 3 x}

y = ∣ x - 3 ∣ - 4

f (x) = 2 x + 3 - 4

\frac{2}{( x - 5 ) ( x + 5 )}

What is the inverse of f(x)=((x-1))/((x+1)) ?
The inverse of f(x)=((x-1))/((x+1)) is (-1-x)/(x-1)