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Popular >

inverse of y=16x^2+1

Solution

inverse

y = 16 x^{2} + 1

Solution

\frac{x - 1}{4}, - \frac{x - 1}{4}

Solution steps

y = 16 x^{2} + 1

Replace

x

with

y

x = 16 y^{2} + 1

Solve for

y, x = 16 y^{2} + 1

\frac{x - 1}{4}, - \frac{x - 1}{4}

Popular Examples

asymptotes of (3x)/(x+4)asymptotes

\frac{3 x}{x + 4}

y = x - 2

asymptotes of f(x)=(x^2-3x+1)/(x-2)asymptotes

f (x) = \frac{x ^{2} - 3 x + 1}{x - 2}

range of f(x)=x^2+5x+6 range

f (x) = x^{2} + 5 x + 6

parity f(x)=(7x^4+3x^2+1)/(3x^4-5x-2)parity

f (x) = \frac{7 x ^{4} + 3 x ^{2} + 1}{3 x ^{4} - 5 x - 2}

Frequently Asked Questions (FAQ)

What is the inverse of y=16x^2+1 ?
The inverse of y=16x^2+1 is (sqrt(x-1))/4 ,-(sqrt(x-1))/4