What is the critical f(x)=x(x-1)^{2/5} ?

The critical f(x)=x(x-1)^{2/5} is x= 5/7 ,x=1

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critical f(x)=x(x-1)^{2/5}

critical points

f (x) = x (x - 1)^{\frac{2}{5}}

x = \frac{5}{7}, x = 1

Solution steps

x (x - 1)^{\frac{2}{5}}

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{5}{7}, x = 1

Identify critical points not in

f (x)

domain

Domain of

x (x - 1)^{\frac{2}{5}} : - \infty < x < \infty

All critical points are in domain

x = \frac{5}{7}, x = 1

f (x) = - \frac{4}{x + 1}

f (x) = x^{2} - 6 x + 8

\frac{4 x ^{2}}{2 x ^{3} - x}

y = 6 - x

m = - 7

What is the critical f(x)=x(x-1)^{2/5} ?
The critical f(x)=x(x-1)^{2/5} is x= 5/7 ,x=1