What is the domain of f(x)=(x+1)/(x^2-9) ?

The domain of f(x)=(x+1)/(x^2-9) is x 3

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domain of f(x)=(x+1)/(x^2-9)

domain

f (x) = \frac{x + 1}{x ^{2} - 9}

x < - 3 or - 3 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 3

The function domain

x < - 3 or - 3 < x < 3 or x > 3

f (x) = x ln (7 x)

\frac{3 x - 6}{x}

h (x) = 2 x - 5

4 + x + 9

\frac{1 - 3 t}{4 + t}

What is the domain of f(x)=(x+1)/(x^2-9) ?
The domain of f(x)=(x+1)/(x^2-9) is x<-3\lor-3<x<3\lor x>3