What is the domain of f(x)=(2x)/(2x^2+3x-20) ?

The domain of f(x)=(2x)/(2x^2+3x-20) is x 5/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(2x)/(2x^2+3x-20)

domain

f (x) = \frac{2 x}{2 x ^{2} + 3 x - 20}

x < - 4 or - 4 < x < \frac{5}{2} or x > \frac{5}{2}

Interval Notation

(- \infty, - 4) \cup (- 4, \frac{5}{2}) \cup (\frac{5}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{5}{2}, x = - 4

The function domain

x < - 4 or - 4 < x < \frac{5}{2} or x > \frac{5}{2}

f (x) = tan (\frac{π x}{2})

f (x) = \frac{6 x - 1}{2 x + 3}

f (x) = 2 - x - 3

f (x) = - x + 9

f (x) = (x^{2} - 25)^{\frac{1}{5}}

What is the domain of f(x)=(2x)/(2x^2+3x-20) ?
The domain of f(x)=(2x)/(2x^2+3x-20) is x<-4\lor-4<x< 5/2 \lor x> 5/2