What is the asymptotes of f(x)=((x^2+3x-4))/(x+1) ?

The asymptotes of f(x)=((x^2+3x-4))/(x+1) is Vertical: x=-1,Slant: y=x+2

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asymptotes of f(x)=((x^2+3x-4))/(x+1)

asymptotes

f (x) = \frac{( x ^{2} + 3 x - 4 )}{x + 1}

Vertical : x = - 1, Slant : y = x + 2

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 3 x - 4}{x + 1} : x = - 1

Horizontal Asymptotes of

\frac{x ^{2} + 3 x - 4}{x + 1} :

None

Slant Asymptotes of

\frac{x ^{2} + 3 x - 4}{x + 1} : y = x + 2

Vertical : x = - 1, Slant : y = x + 2

y = 2 tan (x - \frac{π}{3})

y = 3 x - 4

e^{7 - x^{2}} x - 5

f (x) = \frac{1}{5}

f (x) = 2 x - \frac{1}{7}

What is the asymptotes of f(x)=((x^2+3x-4))/(x+1) ?
The asymptotes of f(x)=((x^2+3x-4))/(x+1) is Vertical: x=-1,Slant: y=x+2