What is the domain of f(x)=sqrt(1-x^2)+sqrt(x^2-1) ?

The domain of f(x)=sqrt(1-x^2)+sqrt(x^2-1) is x=-1\lor x=1

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domain of f(x)=sqrt(1-x^2)+sqrt(x^2-1)

domain

f (x) = 1 - x^{2} + x^{2} - 1

x = - 1 or x = 1

Interval Notation

x = - 1 \cup x = 1

Solution steps

Find non-negative values for radicals:

x = - 1 or x = 1

The function domain

x = - 1 or x = 1

(\frac{3}{4})^{3 x - 2}

f (x) = x^{4} + 12 x^{2} + 42

\frac{1}{x + 7}

f (x) = x^{2} 4 - x^{2}

\frac{1}{x} - 1

What is the domain of f(x)=sqrt(1-x^2)+sqrt(x^2-1) ?
The domain of f(x)=sqrt(1-x^2)+sqrt(x^2-1) is x=-1\lor x=1