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Popular >

extreme f(x)=-2/(x^2-16)

Solution

extreme points

f (x) = - \frac{2}{x ^{2} - 16}

Solution

Minimum (0, \frac{1}{8})

Solution steps

f^{'} (x) = \frac{4 x}{( x ^{2} - 16 ) ^{2}}

Find intervals:

Decreasing

: - \infty < x < - 4,

Decreasing

: - 4 < x < 0,

Increasing

: 0 < x < 4,

Increasing

: 4 < x < \infty

Plug

x = 0

into

- \frac{2}{x ^{2} - 16} : \frac{1}{8}

Minimum (0, \frac{1}{8})

Popular Examples

inverse of f(x)=2x^3+5 inverse

f (x) = 2 x^{3} + 5

inverse of f(x)=(5x+9)/(x+5)inverse

f (x) = \frac{5 x + 9}{x + 5}

extreme f(x)=3x^4+8x^3 extreme points

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extreme ((x-1)^3)/(x^2)extreme points

\frac{( x - 1 ) ^{3}}{x ^{2}}

inverse of f(x)= 2/(x+3)inverse

f (x) = \frac{2}{x + 3}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=-2/(x^2-16) ?
The extreme f(x)=-2/(x^2-16) is Minimum(0, 1/8)