What is the asymptotes of f(x)=(2x^2-3x+5)/(x^2+1) ?

The asymptotes of f(x)=(2x^2-3x+5)/(x^2+1) is Horizontal: y=2

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asymptotes of f(x)=(2x^2-3x+5)/(x^2+1)

asymptotes

f (x) = \frac{2 x ^{2} - 3 x + 5}{x ^{2} + 1}

Horizontal : y = 2

Solution steps

Vertical asymptotes of

\frac{2 x ^{2} - 3 x + 5}{x ^{2} + 1} :

None

Horizontal Asymptotes of

\frac{2 x ^{2} - 3 x + 5}{x ^{2} + 1} : y = 2

Slant Asymptotes of

\frac{2 x ^{2} - 3 x + 5}{x ^{2} + 1} :

None

Horizontal : y = 2

f (x) = 5 x^{2} + 8 x - 2

(x - 5)^{2}

y = tan (\frac{5 x}{6})

f (x) = 0.09 x^{2} + 17 x + 350

\frac{z}{( z + 1 ) ^{2}}

What is the asymptotes of f(x)=(2x^2-3x+5)/(x^2+1) ?
The asymptotes of f(x)=(2x^2-3x+5)/(x^2+1) is Horizontal: y=2