What is the range of f(x)=3sin(2x) ?

The range of f(x)=3sin(2x) is -3<= f(x)<= 3

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range of f(x)=3sin(2x)

range

f (x) = 3 sin (2 x)

- 3 \leq f (x) \leq 3

Interval Notation

[- 3, 3]

Solution steps

The range of the basic

sin

function is

- 1 \leq sin (2 x) \leq 1

- 1 \leq sin (2 x) \leq 1

Multiply the edges of the range by:

3

- 3 \leq 3 sin (2 x) \leq 3

Therefore the range is

- 3 \leq f (x) \leq 3

(0, 5), (- 3, 6)

f (x) = x^{3} + 5 x^{2} - 4 x + 1

(2, 4), (- 3, - 8)

f (t) = t

f (x) = ln (4 - x)

What is the range of f(x)=3sin(2x) ?
The range of f(x)=3sin(2x) is -3<= f(x)<= 3