What is the inverse of f(x)=3x^2+2x ?

The inverse of f(x)=3x^2+2x is (-1+sqrt(3x+1))/3 ,-(sqrt(3x+1)+1)/3

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inverse of f(x)=3x^2+2x

inverse

f (x) = 3 x^{2} + 2 x

\frac{- 1 + 3 x + 1}{3}, - \frac{3 x + 1 + 1}{3}

Solution steps

y = 3 x^{2} + 2 x

Replace

x

with

y

x = 3 y^{2} + 2 y

Solve for

y, x = 3 y^{2} + 2 y

\frac{- 1 + 3 x + 1}{3}, - \frac{3 x + 1 + 1}{3}

f (x) = \frac{1}{x ^{3} - x}

y + 6 = - \frac{1}{5} (x + 3), (- 5, - 9)

lo g_{4} (x - 4)

\frac{x ^{2} + x - 2}{x + 1}

(- 3, - 1), (4, 3)

What is the inverse of f(x)=3x^2+2x ?
The inverse of f(x)=3x^2+2x is (-1+sqrt(3x+1))/3 ,-(sqrt(3x+1)+1)/3