What is the domain of f(x)=x^{1/5}+sqrt(x) ?

The domain of f(x)=x^{1/5}+sqrt(x) is x>= 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=x^{1/5}+sqrt(x)

domain

f (x) = x^{\frac{1}{5}} + x

x \geq 0

Interval Notation

[0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

The function domain

x \geq 0

y = - \frac{5}{4} x + 1, (2, 7)

f (x) = - 8 x + 8

f (x) = - x^{3} + 6 x^{2} - 17

y = x^{4} - 4 x^{2}

f (x) = - 2 (\frac{1}{4})^{x - 3}

What is the domain of f(x)=x^{1/5}+sqrt(x) ?
The domain of f(x)=x^{1/5}+sqrt(x) is x>= 0