What is the f(x)=(sqrt(y^2-1))/y ?

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f(x)=(sqrt(y^2-1))/y

f (x) = \frac{y ^{2} - 1}{y}

Domain : y \leq - 1 or y \geq 1

Range : - 1 < f (x) < 1

X Intercepts : (1, 0), (- 1, 0)

Asymptotes : Horizontal x = 1, x = - 1

Extreme Points : Maximum (- 1, 0), Minimum (1, 0)

Interval Notation

Domain : (- \infty, - 1] \cup [1, \infty)

Range : (- 1, 1)

Solution steps

Domain of

\frac{y ^{2} - 1}{y} : y \leq - 1 or y \geq 1

Range of

\frac{y ^{2} - 1}{y} : - 1 < f (x) < 1

Axis interception points of

\frac{y ^{2} - 1}{y} :

X Intercepts

: (1, 0), (- 1, 0)

Asymptotes of

\frac{y ^{2} - 1}{y} :

Horizontal

: x = 1, x = - 1

Extreme Points of

\frac{y ^{2} - 1}{y} :

Maximum

(- 1, 0),

Minimum

(1, 0)

f (x) = (x - 3)^{2}

f (x) = \frac{4 - e ^{x^{2}}}{1 - e ^{4 - x^{2}}}

ln (x^{2} - 6 x + 8)

f (x) = 1 + x^{2}

f (x) = 5 x - 2 y = 4