What is the domain of (x^3+x^2-6x)/(4x^2+4x-8) ?

The domain of (x^3+x^2-6x)/(4x^2+4x-8) is x 1

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domain of (x^3+x^2-6x)/(4x^2+4x-8)

domain

\frac{x ^{3} + x ^{2} - 6 x}{4 x ^{2} + 4 x - 8}

x < - 2 or - 2 < x < 1 or x > 1

Interval Notation

(- \infty, - 2) \cup (- 2, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 2

The function domain

x < - 2 or - 2 < x < 1 or x > 1

3.54

- x^{2} - 1

f (x) = \frac{9 x}{x ^{2} - 16}

\frac{3 2 ^{2}}{2 ^{2} + 1}

f (x) = 3 x^{5} + x^{3}

What is the domain of (x^3+x^2-6x)/(4x^2+4x-8) ?
The domain of (x^3+x^2-6x)/(4x^2+4x-8) is x<-2\lor-2<x<1\lor x>1