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Popular >

range of f(x)=x^2+4

Solution

range

f (x) = x^{2} + 4

Solution

f (x) \geq 4

+1

Interval Notation

[4, \infty)

Solution steps

Vertex of

x^{2} + 4 :

Minimum

(0, 4)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 1,

Vertex

(x_{v}, y_{v}) = (0, 4)

f (x) \geq 4

Popular Examples

intercepts of log_{3}(x-2)+3 intercepts

lo g_{3} (x - 2) + 3

y = \frac{1}{x - 2}

critical 2/(5x^{3/5)}critical points

\frac{2}{5 x ^{\frac{3}{5}}}

domain of sqrt(t^2+4)domain

t^{2} + 4

inverse of f(x)=(1-sqrt(x))/(1+sqrt(x))inverse

f (x) = \frac{1 - x}{1 + x}

Frequently Asked Questions (FAQ)

What is the range of f(x)=x^2+4 ?
The range of f(x)=x^2+4 is f(x)>= 4