What is the domain of sqrt(t^2+4) ?

The domain of sqrt(t^2+4) is -infinity <t<infinity

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domain of sqrt(t^2+4)

domain

t^{2} + 4

- \infty < t < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < t < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < t < \infty

f (x) = \frac{1 - x}{1 + x}

\frac{3}{3 x + 12}

y = \frac{4 - x ^{2}}{x ^{2} - 1}

f (x) = \frac{x}{x ^{2} - 1}

f (x) = 0.35 x^{2} - 0.7 x - 7

What is the domain of sqrt(t^2+4) ?
The domain of sqrt(t^2+4) is -infinity <t<infinity