What is the inverse of (x^2)/(x-2) ?

The inverse of (x^2)/(x-2) is (x+sqrt(x^2-8x))/2 ,(x-sqrt(x^2-8x))/2

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inverse of (x^2)/(x-2)

inverse

\frac{x ^{2}}{x - 2}

\frac{x + x ^{2} - 8 x}{2}, \frac{x - x ^{2} - 8 x}{2}

Solution steps

y = \frac{x ^{2}}{x - 2}

Replace

x

with

y

x = \frac{y ^{2}}{y - 2}

Solve for

y, x = \frac{y ^{2}}{y - 2}

\frac{x + x ^{2} - 8 x}{2}, \frac{x - x ^{2} - 8 x}{2}

f (x) = \frac{7}{4 x + 1}

(0, 0), (6, 8)

- 6 ∣ x - 3 ∣

f (x) = \frac{2 e ^{x}}{e ^{x} - 6}

f (x) = \frac{7 x ^{2} + 5 x - 2}{2 x ^{2} - 18}

What is the inverse of (x^2)/(x-2) ?
The inverse of (x^2)/(x-2) is (x+sqrt(x^2-8x))/2 ,(x-sqrt(x^2-8x))/2