What is the shift-2-2cos(4/3 x+5pi) ?

The shift-2-2cos(4/3 x+5pi) is Phase:-(15pi)/4 , Vertical:-2

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shift-2-2cos(4/3 x+5pi)

shift

- 2 - 2 cos (\frac{4}{3} x + 5 π)

Phase : - \frac{15 π}{4}, Vertical : - 2

Solution steps

f (x) = - 2 - 2 cos (\frac{4}{3} x + 5 π)

g (B x - C) = cos (\frac{4}{3} x + 5 π), B = \frac{4}{3}, C = - 5 π, D = - 2

Therefore, the phase shift

\frac{C}{B}

\frac{- 5 π}{\frac{4}{3}}

- \frac{15 π}{4}

The vertical shift

D

- 2

- 2

\frac{5}{x + 8}

f (x) = t^{2} - 9

4 t^{2}

\frac{7}{5 x ^{2}}

f (x) = \frac{- 2 x}{x ^{2} + 3}

What is the shift-2-2cos(4/3 x+5pi) ?
The shift-2-2cos(4/3 x+5pi) is Phase:-(15pi)/4 , Vertical:-2