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Popular >

midpoint (-16,2),(4,-11)

Solution

midpoint

(- 16, 2), (4, - 11)

Solution

(- 6, - \frac{9}{2})

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (- 16, 2), (x_{2}, y_{2}) = (4, - 11)

= (\frac{4 - 16}{2}, \frac{- 11 + 2}{2})

Refine

= (- 6, - \frac{9}{2})

Popular Examples

periodicity of y= 1/(2cos(2x))periodicity

y = \frac{1}{2 cos ( 2 x )}

intercepts of 1-2x-x^2 intercepts

1 - 2 x - x^{2}

critical f(x)=x^{7/2}-8x^2 critical points

f (x) = x^{\frac{7}{2}} - 8 x^{2}

critical f(x)=6x critical points

f (x) = 6 x

distance (26.7,-6.3),(32.7,-14.3)distance

(26.7, - 6.3), (32.7, - 14.3)

Frequently Asked Questions (FAQ)

What is the midpoint (-16,2),(4,-11) ?
The midpoint (-16,2),(4,-11) is (-6,-9/2)