What is the domain of (x^2-9)/(x^2-x-12) ?

The domain of (x^2-9)/(x^2-x-12) is x 4

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domain of (x^2-9)/(x^2-x-12)

domain

\frac{x ^{2} - 9}{x ^{2} - x - 12}

x < - 3 or - 3 < x < 4 or x > 4

Interval Notation

(- \infty, - 3) \cup (- 3, 4) \cup (4, \infty)

Solution steps

Find undefined (singularity) points:

x = 4, x = - 3

The function domain

x < - 3 or - 3 < x < 4 or x > 4

15 x + 5 y = 7

x^{2} - x

S (t) = 65000 t + 88000

f (x) = 2 x^{4} - 8 x^{3} + 6 x^{2}

\frac{x}{x ( x - 1 )}

What is the domain of (x^2-9)/(x^2-x-12) ?
The domain of (x^2-9)/(x^2-x-12) is x<-3\lor-3<x<4\lor x>4