What is the asymptotes of f(x)=(9x)/(x^2+4x-5) ?

The asymptotes of f(x)=(9x)/(x^2+4x-5) is Vertical: x=-5,x=1,Horizontal: y=0

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asymptotes of f(x)=(9x)/(x^2+4x-5)

asymptotes

f (x) = \frac{9 x}{x ^{2} + 4 x - 5}

Vertical : x = - 5, x = 1, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{9 x}{x ^{2} + 4 x - 5} : x = - 5, x = 1

Horizontal Asymptotes of

\frac{9 x}{x ^{2} + 4 x - 5} : y = 0

Slant Asymptotes of

\frac{9 x}{x ^{2} + 4 x - 5} :

None

Vertical : x = - 5, x = 1, Horizontal : y = 0

f (x) = \frac{2}{x - 3}

(3, 2), (8, 12)

\frac{x ^{2} + 1}{x + 1}

(1, 5), (0, 0)

y = \frac{1}{2} x + 1

What is the asymptotes of f(x)=(9x)/(x^2+4x-5) ?
The asymptotes of f(x)=(9x)/(x^2+4x-5) is Vertical: x=-5,x=1,Horizontal: y=0