What is the domain of f(x)=(-7)/(2t^{3/2)} ?

The domain of f(x)=(-7)/(2t^{3/2)} is t>0

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domain of f(x)=(-7)/(2t^{3/2)}

domain

f (x) = \frac{- 7}{2 t ^{\frac{3}{2}}}

t > 0

Solution steps

Find non-negative values for radicals:

t \geq 0

Find undefined (singularity) points:

t = 0

Combine real regions and undefined points for final function domain

t > 0

x e^{- 8 x}

x^{2} - 4 x

f (x) = 5 x - 4

7 x + 6 y = 17

y = 16

What is the domain of f(x)=(-7)/(2t^{3/2)} ?
The domain of f(x)=(-7)/(2t^{3/2)} is t>0