What is the critical f(x)= x/(x^2+6x+5) ?

The critical f(x)= x/(x^2+6x+5) is x=-sqrt(5),x=sqrt(5)

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critical f(x)= x/(x^2+6x+5)

critical points

f (x) = \frac{x}{x ^{2} + 6 x + 5}

x = - 5, x = 5

Solution steps

\frac{x}{x ^{2} + 6 x + 5}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 5, x = 5, x = - 5, x = - 1

Identify critical points not in

f (x)

domain

Domain of

\frac{x}{x ^{2} + 6 x + 5} : x < - 5 or - 5 < x < - 1 or x > - 1

\frac{x}{x ^{2} + 6 x + 5}

is not defined at

x = - 5, x = - 1

, therefore:

x = - 5, x = 5

f (x) = - 2 x + 14

(x - 3) x

y = - 6 x + 3

f (x) = \frac{x ^{3}}{x + 1}

f (x) = \frac{2 - x}{( x - 1 ) ( 2 x - 1 )}

What is the critical f(x)= x/(x^2+6x+5) ?
The critical f(x)= x/(x^2+6x+5) is x=-sqrt(5),x=sqrt(5)