What is the domain of sqrt(3-\sqrt{x^2-16)} ?

The domain of sqrt(3-\sqrt{x^2-16)} is -5<= x<=-4\lor 4<= x<= 5

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domain of sqrt(3-\sqrt{x^2-16)}

domain

3 - x^{2} - 16

- 5 \leq x \leq - 4 or 4 \leq x \leq 5

Interval Notation

[- 5, - 4] \cup [4, 5]

Solution steps

Find non-negative values for radicals:

- 5 \leq x \leq - 4 or 4 \leq x \leq 5

The function domain

- 5 \leq x \leq - 4 or 4 \leq x \leq 5

f (x) = \frac{x + 2}{x - 3}

f (x) = 2 (x + 2) (x + 6)

f (x) = 1 - e^{x}

y = 9 x - 2

3^{x} - 3

What is the domain of sqrt(3-\sqrt{x^2-16)} ?
The domain of sqrt(3-\sqrt{x^2-16)} is -5<= x<=-4\lor 4<= x<= 5