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Popular >

distance (-1,1),(-2,-1)

Solution

distance

(- 1, 1), (- 2, - 1)

Solution

5

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(- 1, 1)

and

(- 2, - 1)

is

= (- 2 - (- 1))^{2} + (- 1 - 1)^{2}

Simplify

= 5

Popular Examples

inverse of 2x^2+7 inverse

2 x^{2} + 7

critical f(x)=x^4-8x^2+8 critical points

f (x) = x^{4} - 8 x^{2} + 8

asymptotes of f(x)=((x+1))/((x))asymptotes

f (x) = \frac{( x + 1 )}{( x )}

extreme f(x)=x^2+3 extreme points

f (x) = x^{2} + 3

inverse of f(x)=(x+3)/(x-5)inverse

f (x) = \frac{x + 3}{x - 5}

Frequently Asked Questions (FAQ)

What is the distance (-1,1),(-2,-1) ?
The distance (-1,1),(-2,-1) is square root of 5