What is the inverse of f(x)=((x-7))/((x+7)) ?

The inverse of f(x)=((x-7))/((x+7)) is (-7-7x)/(x-1)

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inverse of f(x)=((x-7))/((x+7))

inverse

f (x) = \frac{( x - 7 )}{( x + 7 )}

\frac{- 7 - 7 x}{x - 1}

Solution steps

y = \frac{x - 7}{x + 7}

Replace

x

with

y

x = \frac{y - 7}{y + 7}

Solve for

y, x = \frac{y - 7}{y + 7}

\frac{- 7 - 7 x}{x - 1}

\frac{17}{4} (x + 2)^{2}

\frac{1}{5} x^{3} - 4

f (x) = 5 [\frac{x + 3}{4} - 2]^{2} + 6

(\frac{1}{2}, \frac{1}{3}), (\frac{3}{2}, \frac{5}{3})

f (x) = - 5 x^{2} + 6 x - 3

What is the inverse of f(x)=((x-7))/((x+7)) ?
The inverse of f(x)=((x-7))/((x+7)) is (-7-7x)/(x-1)