What is the perpendicular y=2x+7,(4,-8) ?

The perpendicular y=2x+7,(4,-8) is y=-1/2 x-6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

perpendicular y=2x+7,(4,-8)

perpendicular

y = 2 x + 7, (4, - 8)

y = - \frac{1}{2} x - 6

Solution steps

Find the line

y = mx + b

perpendicular to

y = 2 x + 7

that passes through

(4, - 8)

Find the slope of

y = 2 x + 7 : m = 2

Compute the slope of the perpendicular line:

m_{p} = - \frac{1}{2}

Find the line with slope m=

- \frac{1}{2}

and passing through

(4, - 8) : y = - \frac{1}{2} x - 6

y = - \frac{1}{2} x - 6

y = 3 x + 7

f (x) = \frac{x}{1 - x ^{2}}

f (x) = - \frac{1}{2} ∣ x - 6 ∣ + 1

f (x) = 4 x

f (x) = \frac{2 x + 5}{x - 3}

What is the perpendicular y=2x+7,(4,-8) ?
The perpendicular y=2x+7,(4,-8) is y=-1/2 x-6