What is the domain of f(x)= 1/(x^3-6x^2+5x+12) ?

The domain of f(x)= 1/(x^3-6x^2+5x+12) is x 4

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domain of f(x)= 1/(x^3-6x^2+5x+12)

domain

f (x) = \frac{1}{x ^{3} - 6 x ^{2} + 5 x + 12}

x < - 1 or - 1 < x < 3 or 3 < x < 4 or x > 4

Interval Notation

(- \infty, - 1) \cup (- 1, 3) \cup (3, 4) \cup (4, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1, x = 3, x = 4

The function domain

x < - 1 or - 1 < x < 3 or 3 < x < 4 or x > 4

113 t - 0.5 t^{4} + 900

f (x) = 3 x^{\frac{2}{3}} - x

y = 5 x - 4

6 x + y = 10

(- 1, 5), (- 6, - 2)

What is the domain of f(x)= 1/(x^3-6x^2+5x+12) ?
The domain of f(x)= 1/(x^3-6x^2+5x+12) is x<-1\lor-1<x<3\lor 3<x<4\lor x>4