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Popular >

distance (0,-5),(7,2)

Solution

distance

(0, - 5), (7, 2)

Solution

72

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(0, - 5)

and

(7, 2)

is

= (7 - 0)^{2} + (2 - (- 5))^{2}

Simplify

= 72

Popular Examples

domain of f(x)=sqrt(3-|x-2|)domain

f (x) = 3 - ∣ x - 2 ∣

asymptotes of f(x)=(x^2-3x-4)/(2x+2)asymptotes

f (x) = \frac{x ^{2} - 3 x - 4}{2 x + 2}

domain of f(x)=sqrt((x-7)/(6-x))domain

f (x) = \frac{x - 7}{6 - x}

domain of f(x)=(sqrt(x+5))/(x^2+3x-10)domain

f (x) = \frac{x + 5}{x ^{2} + 3 x - 10}

asymptotes of f(x)=(x+2)/(x^2+2x-24)asymptotes

f (x) = \frac{x + 2}{x ^{2} + 2 x - 24}

Frequently Asked Questions (FAQ)

What is the distance (0,-5),(7,2) ?
The distance (0,-5),(7,2) is 7sqrt(2)