What is the domain of sqrt(x^2+9) ?

The domain of sqrt(x^2+9) is -infinity <x<infinity

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domain of sqrt(x^2+9)

domain

x^{2} + 9

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = 2 x 3 x - 1

f (x) = \frac{- 4 x ^{2} - 2 x + 1}{2 x + 3}

f (x) = 7 x - 42 + 2

f (x) = \frac{3 x + 2}{5 x - 2}

y = 8 - 7 x - x^{3}

What is the domain of sqrt(x^2+9) ?
The domain of sqrt(x^2+9) is -infinity <x<infinity