What is the inverse of f(x)=2(x-3)^3+6 ?

The inverse of f(x)=2(x-3)^3+6 is \sqrt[3]{(x-6)/2}+3

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inverse of f(x)=2(x-3)^3+6

inverse

f (x) = 2 (x - 3)^{3} + 6

Solution steps

y = 2 (x - 3)^{3} + 6

Replace

x

with

y

x = 2 (y - 3)^{3} + 6

Solve for

y, x = 2 (y - 3)^{3} + 6

f (x) = 3 - 2 x e n e l (- 1.5)

f (x) = x^{\frac{15}{7}} - x^{\frac{8}{7}}

\frac{x ^{2} + 12}{3}

f (x) = a y = 3 x - 1

f (x) = ln ((2 x + 3) + \frac{1}{x})

What is the inverse of f(x)=2(x-3)^3+6 ?
The inverse of f(x)=2(x-3)^3+6 is \sqrt[3]{(x-6)/2}+3