What is the inverse of f(x)=((x-3)^7+1)/7 ?

The inverse of f(x)=((x-3)^7+1)/7 is \sqrt[7]{7x-1}+3

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inverse of f(x)=((x-3)^7+1)/7

inverse

f (x) = \frac{( x - 3 ) ^{7} + 1}{7}

Solution steps

y = \frac{( x - 3 ) ^{7} + 1}{7}

Replace

x

with

y

x = \frac{( y - 3 ) ^{7} + 1}{7}

Solve for

y, x = \frac{( y - 3 ) ^{7} + 1}{7}

3 x^{4} - 18 x^{2}

f (x) = \frac{x + 4}{x ^{2}}

f (x) = x + 18

f (x) = - \frac{2}{x ^{3}}

What is the inverse of f(x)=((x-3)^7+1)/7 ?
The inverse of f(x)=((x-3)^7+1)/7 is \sqrt[7]{7x-1}+3