What is the domain of f(x)= 1/(2sqrt(9-x)) ?

The domain of f(x)= 1/(2sqrt(9-x)) is x<9

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domain of f(x)= 1/(2sqrt(9-x))

domain

f (x) = \frac{1}{2 9 - x}

x < 9

Interval Notation

(- \infty, 9)

Solution steps

Find non-negative values for radicals:

x \leq 9

Find undefined (singularity) points:

x = 9

Combine real regions and undefined points for final function domain

x < 9

f (x) = x^{2} + y^{2} = 4

11 x + 6 y = 3

f (x) = x^{2} + 9 x

- \frac{1 - cos ( 4 x )}{1 + cos ( 4 x )}

h (t) = - 4.9 (t + 3)^{2} + 45.8

What is the domain of f(x)= 1/(2sqrt(9-x)) ?
The domain of f(x)= 1/(2sqrt(9-x)) is x<9