What is the inverse of y=12000-(11800)/(x+1) ?

The inverse of y=12000-(11800)/(x+1) is (-x+200)/(x-12000)

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inverse of y=12000-(11800)/(x+1)

inverse

y = 12000 - \frac{11800}{x + 1}

\frac{- x + 200}{x - 12000}

Solution steps

y = 12000 - \frac{11800}{x + 1}

Replace

x

with

y

x = 12000 - \frac{11800}{y + 1}

Solve for

y, x = 12000 - \frac{11800}{y + 1}

\frac{- x + 200}{x - 12000}

y = lo g_{10} (x + 3)

tan (\frac{π}{3} x)

f (x) = \frac{x}{9 x + 5}

2 x^{3} - x

f (x) = 2 x^{2} + 4 x - 10

What is the inverse of y=12000-(11800)/(x+1) ?
The inverse of y=12000-(11800)/(x+1) is (-x+200)/(x-12000)