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Popular >

inverse of h(n)= 1/n+1

Solution

inverse

h (n) = \frac{1}{n} + 1

Solution

\frac{1}{n - 1}

Solution steps

y = \frac{1}{n} + 1

Replace

n

with

y

n = \frac{1}{y} + 1

Solve for

y, n = \frac{1}{y} + 1

\frac{1}{n - 1}

Popular Examples

domain of f(x)=sqrt(7x+6)domain

f (x) = 7 x + 6

domain of ln(16-t^2)domain

ln (16 - t^{2})

y = 9 - x^{2}

domain of e^{sqrt(x)}domain

e^{x}

domain of (x-6)/(x-25)domain

\frac{x - 6}{x - 25}

Frequently Asked Questions (FAQ)

What is the inverse of h(n)= 1/n+1 ?
The inverse of h(n)= 1/n+1 is 1/(n-1)