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Popular >

distance (3,10),(10,11)

Solution

distance

(3, 10), (10, 11)

Solution

52

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(3, 10)

and

(10, 11)

is

= (10 - 3)^{2} + (11 - 10)^{2}

Simplify

= 52

Popular Examples

inverse of f(x)=((x-1))/x inverse

f (x) = \frac{( x - 1 )}{x}

parity y=sqrt(2x^2-5x^8)parity

y = 2 x^{2} - 5 x^{8}

inverse of f(x)= 1/2 x-1 inverse

f (x) = \frac{1}{2} x - 1

domain of f(x)=(x-2)/(x^3+x)domain

f (x) = \frac{x - 2}{x ^{3} + x}

domain of f(x)=(sqrt(5x))/(7x-8)domain

f (x) = \frac{5 x}{7 x - 8}

Frequently Asked Questions (FAQ)

What is the distance (3,10),(10,11) ?
The distance (3,10),(10,11) is 5sqrt(2)