What is the critical f(x)=xe^{-x^2} ?

The critical f(x)=xe^{-x^2} is x=-1/(sqrt(2)),x= 1/(sqrt(2))

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critical f(x)=xe^{-x^2}

critical points

f (x) = x e^{- x^{2}}

x = - \frac{1}{2}, x = \frac{1}{2}

Solution steps

x e^{- x^{2}}

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{1}{2}, x = \frac{1}{2}

Identify critical points not in

f (x)

domain

Domain of

x e^{- x^{2}} : - \infty < x < \infty

All critical points are in domain

x = - \frac{1}{2}, x = \frac{1}{2}

(12, 0), (0, 6)

f (x) = e^{x} + 1

f (x) = x + 3

f (x) = \frac{2}{3 x + 2}

f (x) = \frac{( x ^{2} + 7 x )}{( 6 x ^{2} - 1 )}

What is the critical f(x)=xe^{-x^2} ?
The critical f(x)=xe^{-x^2} is x=-1/(sqrt(2)),x= 1/(sqrt(2))