What is the domain of sqrt(x/(x-1)) ?

The domain of sqrt(x/(x-1)) is x 1

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domain of sqrt(x/(x-1))

domain

\frac{x}{x - 1}

x \leq 0 or x > 1

Interval Notation

(- \infty, 0] \cup (1, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x > 1

Find undefined (singularity) points:

x = 1

Combine real regions and undefined points for final function domain

x \leq 0 or x > 1

y = \frac{5}{2} x - \frac{13}{2}

f (x) = \frac{2 x - 10}{5}

y = 1 - x

f (x) = x^{2} + 8 x + 15

(\frac{1}{2})^{x + 4} - 3

What is the domain of sqrt(x/(x-1)) ?
The domain of sqrt(x/(x-1)) is x<= 0\lor x>1