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Popular >

distance (5,-1),(-1,5)

Solution

distance

(5, - 1), (- 1, 5)

Solution

62

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(5, - 1)

and

(- 1, 5)

is

= (- 1 - 5)^{2} + (5 - (- 1))^{2}

Simplify

= 62

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f (x) = x^{2} + 6 x + 34

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f (x) = \frac{( x + 2 )}{x - 3}

inverse of (e^x+e^{-x})/2 inverse

\frac{e ^{x} + e ^{- x}}{2}

simplify (0)(14.14)simplify

(0) (14.14)

shift f(x)=-3cos(1/3 x-pi)+4 shift

f (x) = - 3 cos (\frac{1}{3} x - π) + 4

Frequently Asked Questions (FAQ)

What is the distance (5,-1),(-1,5) ?
The distance (5,-1),(-1,5) is 6sqrt(2)